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	<title>Comments on: The Lazy Rule of Thirds</title>
	<atom:link href="http://www.jakegarn.com/the-rule-of-thirds/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.jakegarn.com/the-rule-of-thirds/</link>
	<description>Whimsical fashion photographer</description>
	<lastBuildDate>Thu, 02 Feb 2012 05:13:34 +0000</lastBuildDate>
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		<title>By: how to make twitter followers</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15878</link>
		<dc:creator>how to make twitter followers</dc:creator>
		<pubDate>Mon, 09 Jan 2012 08:00:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15878</guid>
		<description>Very great post. I just stumbled upon your blog and wished to say that I&#039;ve truly enjoyed surfing around your weblog posts. After all I will be subscribing for your feed and I&#039;m hoping you write once more very soon!</description>
		<content:encoded><![CDATA[<p>Very great post. I just stumbled upon your blog and wished to say that I&#8217;ve truly enjoyed surfing around your weblog posts. After all I will be subscribing for your feed and I&#8217;m hoping you write once more very soon!</p>
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	<item>
		<title>By: Alysha</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15665</link>
		<dc:creator>Alysha</dc:creator>
		<pubDate>Wed, 14 Dec 2011 01:39:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15665</guid>
		<description>So True.</description>
		<content:encoded><![CDATA[<p>So True.</p>
]]></content:encoded>
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	<item>
		<title>By: Chelsea</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-1/#comment-15634</link>
		<dc:creator>Chelsea</dc:creator>
		<pubDate>Thu, 01 Dec 2011 20:54:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15634</guid>
		<description>You, sir... Are quite witty. Reminds me slightly of David Thorne. :) You should check out his blog http://27bslash6.com/index.html : )</description>
		<content:encoded><![CDATA[<p>You, sir&#8230; Are quite witty. Reminds me slightly of David Thorne. <img src='http://www.jakegarn.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' />  You should check out his blog <a href="http://27bslash6.com/index.html" rel="nofollow">http://27bslash6.com/index.html</a> : )</p>
]]></content:encoded>
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	<item>
		<title>By: Jake Garn</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15624</link>
		<dc:creator>Jake Garn</dc:creator>
		<pubDate>Mon, 28 Nov 2011 21:42:08 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15624</guid>
		<description>Photographer is just fine I suppose, but call me whatever you&#039;d like!</description>
		<content:encoded><![CDATA[<p>Photographer is just fine I suppose, but call me whatever you&#8217;d like!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Roger Wehage</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15583</link>
		<dc:creator>Roger Wehage</dc:creator>
		<pubDate>Fri, 18 Nov 2011 19:57:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15583</guid>
		<description>What they don&#039;t teach in photography class...

The radius of the ith section of the spiral is:

(phi – 1)^i = (F_(i+1) – F_i * phi) * (–1)^i; i = 0, 1, ...

where

phi = 1.6180... 

phi – 1 = 0.6180...

and

F_i = F_(i–2) + F_(i–1); F_0 = 0; F_1 = 1; F_2 = 1; etc.

is the ith Fibonacci number.

For example

(phi – 1)^7 = (0.6180...)^7 = (21 – 13 * 1.6180...) * (–1)^7 = 0.03444185...

(phi – 1)^8 = (0.6180...)^8 = (44 – 21 * 1.6180...) * (–1)^8 = 0.02128623...

And just for fun,

phi^i = F_(i–1) + F_i * phi; i = 0, 1, ...

In this case:

phi^7 = (1.6180...)^7 =   8 + 13 * 1.6180... = 29.03444185...

phi^8 = (1.6180...)^8 = 13 + 21 * 1.6180... = 46.97871376...

Food for thought: 

phi^7 – (phi – 1)^7 = 29.00000000000000...

phi^8 – (phi – 1)^8 = 46.95742752749569...

phi^8 + (phi – 1)^8 = 47.00000000000000...

phi^i – (phi – 1)^i = F_(i–1) – F_(i+1) * (–1)^i +  F_i * phi * (1 + (–1)^i)

Note:

(1 + (–1)^i) = 0 when i is odd

(1 + (–1)^i) = 2 when i is even</description>
		<content:encoded><![CDATA[<p>What they don&#8217;t teach in photography class&#8230;</p>
<p>The radius of the ith section of the spiral is:</p>
<p>(phi – 1)^i = (F_(i+1) – F_i * phi) * (–1)^i; i = 0, 1, &#8230;</p>
<p>where</p>
<p>phi = 1.6180&#8230; </p>
<p>phi – 1 = 0.6180&#8230;</p>
<p>and</p>
<p>F_i = F_(i–2) + F_(i–1); F_0 = 0; F_1 = 1; F_2 = 1; etc.</p>
<p>is the ith Fibonacci number.</p>
<p>For example</p>
<p>(phi – 1)^7 = (0.6180&#8230;)^7 = (21 – 13 * 1.6180&#8230;) * (–1)^7 = 0.03444185&#8230;</p>
<p>(phi – 1)^8 = (0.6180&#8230;)^8 = (44 – 21 * 1.6180&#8230;) * (–1)^8 = 0.02128623&#8230;</p>
<p>And just for fun,</p>
<p>phi^i = F_(i–1) + F_i * phi; i = 0, 1, &#8230;</p>
<p>In this case:</p>
<p>phi^7 = (1.6180&#8230;)^7 =   8 + 13 * 1.6180&#8230; = 29.03444185&#8230;</p>
<p>phi^8 = (1.6180&#8230;)^8 = 13 + 21 * 1.6180&#8230; = 46.97871376&#8230;</p>
<p>Food for thought: </p>
<p>phi^7 – (phi – 1)^7 = 29.00000000000000&#8230;</p>
<p>phi^8 – (phi – 1)^8 = 46.95742752749569&#8230;</p>
<p>phi^8 + (phi – 1)^8 = 47.00000000000000&#8230;</p>
<p>phi^i – (phi – 1)^i = F_(i–1) – F_(i+1) * (–1)^i +  F_i * phi * (1 + (–1)^i)</p>
<p>Note:</p>
<p>(1 + (–1)^i) = 0 when i is odd</p>
<p>(1 + (–1)^i) = 2 when i is even</p>
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	</item>
	<item>
		<title>By: M B A Khan</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15576</link>
		<dc:creator>M B A Khan</dc:creator>
		<pubDate>Wed, 16 Nov 2011 22:18:21 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15576</guid>
		<description>So true... I have been looking forward to read something out of the box since last quite a few months and your post has fulfilled my desire... 

Thanks</description>
		<content:encoded><![CDATA[<p>So true&#8230; I have been looking forward to read something out of the box since last quite a few months and your post has fulfilled my desire&#8230; </p>
<p>Thanks</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Saroni</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-15482</link>
		<dc:creator>Saroni</dc:creator>
		<pubDate>Sun, 06 Nov 2011 07:06:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-15482</guid>
		<description>Hey very great artwork,
What type of person are you called since you do this type of art.
Are you just called an artist or are you called something else.</description>
		<content:encoded><![CDATA[<p>Hey very great artwork,<br />
What type of person are you called since you do this type of art.<br />
Are you just called an artist or are you called something else.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Anurag</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-14595</link>
		<dc:creator>Anurag</dc:creator>
		<pubDate>Sat, 17 Sep 2011 15:45:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-14595</guid>
		<description>For the first time i heard of such an excellent recommendation....and this post is awesome...
&quot; I am recommending that you do is to start seeing the world in a way that Mother Nature tends to see the world, and that is in a proportion that is absolutely elegant in it’s mathematical beauty.&quot;

M still a novice photographerBeing lover of nature &amp; it&#039;s beauty..... Your recommendation is very precious to me.

Thanks Alot :)</description>
		<content:encoded><![CDATA[<p>For the first time i heard of such an excellent recommendation&#8230;.and this post is awesome&#8230;<br />
&#8221; I am recommending that you do is to start seeing the world in a way that Mother Nature tends to see the world, and that is in a proportion that is absolutely elegant in it’s mathematical beauty.&#8221;</p>
<p>M still a novice photographerBeing lover of nature &amp; it&#8217;s beauty&#8230;.. Your recommendation is very precious to me.</p>
<p>Thanks Alot <img src='http://www.jakegarn.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
]]></content:encoded>
	</item>
	<item>
		<title>By: 70 Useful Photography Articles for Beginners &#124; TheWorld365 &#124; Nuno &#38; Debora Photography</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-13929</link>
		<dc:creator>70 Useful Photography Articles for Beginners &#124; TheWorld365 &#124; Nuno &#38; Debora Photography</dc:creator>
		<pubDate>Thu, 18 Aug 2011 04:02:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-13929</guid>
		<description>[...] The Lazy Rule of Thirds (Jake Garn) [...]</description>
		<content:encoded><![CDATA[<p>[...] The Lazy Rule of Thirds (Jake Garn) [...]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Kenneth Chan</title>
		<link>http://www.jakegarn.com/the-rule-of-thirds/comment-page-5/#comment-13851</link>
		<dc:creator>Kenneth Chan</dc:creator>
		<pubDate>Sat, 13 Aug 2011 15:53:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.jakegarn.com/?p=217#comment-13851</guid>
		<description>Thanks for the explanation and sample images! I want to continue to learn to see better and be less &quot;lazy&quot; in my composition.</description>
		<content:encoded><![CDATA[<p>Thanks for the explanation and sample images! I want to continue to learn to see better and be less &#8220;lazy&#8221; in my composition.</p>
]]></content:encoded>
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